A METHOD TO FIND OUT THE WEEK DAY FOR ANY DATE
1 week = 7 days
1 year = 365 days
If we divide 365 by 7
We get 7) 365 (52
35
____
15
14
_____
1
_____
So, when we divide 365 days (=1 year) by 7 we get a remainder 1
For 1 year the reminder is 1
For 100 years the remainder will be (100 *1) = 100
In 100 years the No of Leap year = 24
___
124
___
If we divide 124 by 7, we get a remainder 5
7) 124 (17
7
____
54
49
_____
5
_____
For 1 year the reminder = 1
For 100 years the remainder = 5
For 400 years the remainder = (4*5) = 20
(400th year is leap year, hence add 1) 1
___
21
___
(100th, 200th and 300th years are not leap years, whereas 400th year is leap year)
If we divide 21 by 7 we get a remainder 0
7) 21(3
21
--------
0
-------
If we summarize the above,
For 1 year the reminder = 1
For 100 years the remainder = 5
For 400 years the remainder = 0
Example1
28-07- 1968
To find out a week day for the given year, we have to calculate remainder for the year previous to the given year.
Here the given year is 1968, so we have to find out the remainder for the year 1967
We can write the year 1967 as below
The remainders we get when divide by 7
(4*400) = 1600 = 4*0 = 00 = 00
(3*100) = 300 = (3*5) =15 = 01 (15/7= Quotient =2, Remainder =1)
(67*1) = 67 = 04 (67/7=Quotient =9, Remainder =4)
In 67 years the No leap years = 16 = 02(16/7= Quotient =2, Remainder =2)
------
07
------
Remainder for the year 1967 = 07
Jan 1968 = 31
Feb 1968 = 29 (Year 1968 is a leap year)
Mar 1968 = 31
Apr 1968 = 30
May 1968 = 31
Jun 1968 = 30
July 1968 = 28
-----
217
-----
7)217(31
217
-------
0
--------
If the remainder is 0 the day is Sunday
If the remainder is 1 the day is Monday
If the remainder is 2 the day is Tuesday
If the remainder is 3 the day is Wednesday
If the remainder is 4 the day is Thursday
If the remainder is 5 the day is Friday
If the remainder is 6 the day is Saturday
28-07-1968 is Sunday
Example 2
02-12-2011
Here the given year is 2011, so we have to find out the remainder for the year 2010
We can write the year 2010 as below
The remainders we get when divide by 7
(4*400)= 2000= 4*0 = 00
(10*1) = 10 = 03 (10/7=Quotient =1, Remainder =3)
In 10 years the No. of leap years = 02
-----
05
-----
Remainder for the year 2010= 05
Jan 2011 = 31
Feb 2011 = 28 (Year 2011 is not a leap year)
Mar 2011 = 31
Apr 2011 = 30
May 2011 = 31
Jun 2011 = 30
July 2011 = 31
Aug 2011 = 31
Sept 2011 = 30
Oct 2011 = 31
Nov 2011 = 30
Dec 2011 = 02
-----
341
-----
7)341(48
28
-------
61
56
-------
05
-------
Remainder 05 = Friday
1 week = 7 days
1 year = 365 days
If we divide 365 by 7
We get 7) 365 (52
35
____
15
14
_____
1
_____
So, when we divide 365 days (=1 year) by 7 we get a remainder 1
For 1 year the reminder is 1
For 100 years the remainder will be (100 *1) = 100
In 100 years the No of Leap year = 24
___
124
___
If we divide 124 by 7, we get a remainder 5
7) 124 (17
7
____
54
49
_____
5
_____
For 1 year the reminder = 1
For 100 years the remainder = 5
For 400 years the remainder = (4*5) = 20
(400th year is leap year, hence add 1) 1
___
21
___
(100th, 200th and 300th years are not leap years, whereas 400th year is leap year)
If we divide 21 by 7 we get a remainder 0
7) 21(3
21
--------
0
-------
If we summarize the above,
For 1 year the reminder = 1
For 100 years the remainder = 5
For 400 years the remainder = 0
Example1
28-07- 1968
To find out a week day for the given year, we have to calculate remainder for the year previous to the given year.
Here the given year is 1968, so we have to find out the remainder for the year 1967
We can write the year 1967 as below
The remainders we get when divide by 7
(4*400) = 1600 = 4*0 = 00 = 00
(3*100) = 300 = (3*5) =15 = 01 (15/7= Quotient =2, Remainder =1)
(67*1) = 67 = 04 (67/7=Quotient =9, Remainder =4)
In 67 years the No leap years = 16 = 02(16/7= Quotient =2, Remainder =2)
------
07
------
Remainder for the year 1967 = 07
Jan 1968 = 31
Feb 1968 = 29 (Year 1968 is a leap year)
Mar 1968 = 31
Apr 1968 = 30
May 1968 = 31
Jun 1968 = 30
July 1968 = 28
-----
217
-----
7)217(31
217
-------
0
--------
If the remainder is 0 the day is Sunday
If the remainder is 1 the day is Monday
If the remainder is 2 the day is Tuesday
If the remainder is 3 the day is Wednesday
If the remainder is 4 the day is Thursday
If the remainder is 5 the day is Friday
If the remainder is 6 the day is Saturday
28-07-1968 is Sunday
Example 2
02-12-2011
Here the given year is 2011, so we have to find out the remainder for the year 2010
We can write the year 2010 as below
The remainders we get when divide by 7
(4*400)= 2000= 4*0 = 00
(10*1) = 10 = 03 (10/7=Quotient =1, Remainder =3)
In 10 years the No. of leap years = 02
-----
05
-----
Remainder for the year 2010= 05
Jan 2011 = 31
Feb 2011 = 28 (Year 2011 is not a leap year)
Mar 2011 = 31
Apr 2011 = 30
May 2011 = 31
Jun 2011 = 30
July 2011 = 31
Aug 2011 = 31
Sept 2011 = 30
Oct 2011 = 31
Nov 2011 = 30
Dec 2011 = 02
-----
341
-----
7)341(48
28
-------
61
56
-------
05
-------
Remainder 05 = Friday
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